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Given the value of Rydberg constant is 10^(7) m^(-1) the wave number of the last line of the Balmer series in hydrogen spectrum will be |
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Answer» `0.5xx10^(7)m^(-1)` `(1)/(LAMBDA)=R[(1)/(2^(2))-(1)/(OO^(2))]` For final line` n=oo` `(1)/(lambda)=(R)/(4)=(10^(7))/(4)` `:.(1)/(lambda)=0.25xx10^(7)m^(-1)` `:.` Wave number `0.25xx10^(7)m^(-1)` |
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