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Given three points are `A(-3,-2,0),B(3,-3,1)a n dC(5,0,2)dot`Then find a vector having the same directionas that of ` vec A B`and magnitude equal to `| vec A C|dot` |
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Answer» Given points are `A(-3, -2, 0), B(3, -3, 1) and C(5, 0, 2)`. Therefore, `" "vec(AB)=6hati-hatj+hatk` and `" "vec(AC)=8hati+2hatj+2hatk` `" "|vec(AC)|=sqrt(64+4+4)=sqrt(72)` Unit vector in direction of `vec(AB)` is `(6hati-hatj+hatk)/(sqrt(38))` `therefore" "`Required vector `" "=(sqrt(72))/(sqrt(38))(6hati-hatj+hatk)= (6)/(sqrt(19))(6hati-hatj+hatk)` |
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