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Given three straight lines `2x+11 y-5=0,24 x+7y-20=0,`and `4x-3y-2=0`. Then,they form a triangleone line bisects the angle between the other twotwo of them are parallelA. they from a triangleB. they are concurrentC. one line bisects the angle between the other twoD. two of them are parallel |
Answer» Correct Answer - C For the two lines 24x+7y-20=0 and 4x-3y-2=0, the angle bisectors are given by `(24x+7y-20)/(25) =+-(4x-3y-2)/(5)` Taking positive sign, we get 2x+11y-5=0 |
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