1.

Given two vectors veca= -hati +hatj + 2hatk and vecb =- hati - 2 hatj -hatk

Answer»


Solution :a. `vecaxxvecb=|{:(HATI,hatj,hatk),(-1,1,2),(-1,-2,-1):}|=3hati'-3hatj+3hatk`
Hence, the AREA of the triangle is `(3SQRT3)/2`
b. The area of the parallelogram is `3sqrt3`
C. The area of a paralleogram whose diagonals are
`2 veca and 4vecb is 1/2 |2 veca xx 4vecb|=12sqrt3`
d. VOLUME of the parallelpiped
`= |(veca xx vecb).vecc|=sqrt(9+36+9)= 3sqrt6`


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