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Given two vectors veca= -hati +hatj + 2hatk and vecb =- hati - 2 hatj -hatk |
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Answer» Hence, the AREA of the triangle is `(3SQRT3)/2` b. The area of the parallelogram is `3sqrt3` C. The area of a paralleogram whose diagonals are `2 veca and 4vecb is 1/2 |2 veca xx 4vecb|=12sqrt3` d. VOLUME of the parallelpiped `= |(veca xx vecb).vecc|=sqrt(9+36+9)= 3sqrt6` |
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