Given VDD = 25V, VP = -3V. When VGS = -3V, IDS = 10mA. Find the operating point of the circuit.(a) -3.83V, 0.766mA(b) -2.345V, 0.469mA(c) 3.83V, 0.469mA(d) 2.3V, 0.7mAThis question was addressed to me during an interview.I want to ask this question from Biasing of JFET and MOSFET topic in chapter FET Amplifiers of Analog Circuits

Given VDD = 25V, VP = -3V. When VGS = -3V, IDS = 10mA. Find the operat

1.	Given VDD = 25V, VP = -3V. When VGS = -3V, IDS = 10mA. Find the operating point of the circuit.(a) -3.83V, 0.766mA(b) -2.345V, 0.469mA(c) 3.83V, 0.469mA(d) 2.3V, 0.7mAThis question was addressed to me during an interview.I want to ask this question from Biasing of JFET and MOSFET topic in chapter FET Amplifiers of Analog Circuits
Answer» RIGHT choice is (b) -2.345V, 0.469mA Easiest explanation: When VGS = VP then IDSS = IDS = 10mA Also, in above circuit, VGS = -IDSRS = – IDSx5k Thus, IDS = IDSS(1-VGS/VP)^2 Solving we get, IDS = 0.766mA, 0.469mA Thus we get VGS = -3.83V, -2.345V However, VGS should lie between 0 and VP.

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