Given vec(A) = 2hat(i) + 4hat(j) -6hat(k). When a vector vec(B) is added to vec(A) , we get a unit vector along x-axis. Then vec(B) is :

Given vec(A) = 2hat(i) + 4hat(j) -6hat(k). When a vector vec(B) is add

1.	Given vec(A) = 2hat(i) + 4hat(j) -6hat(k). When a vector vec(B) is added to vec(A) , we get a unit vector along x-axis. Then vec(B) is :
Answer» `hat(i) + 2hat(j) - 3hat(K)` `-hat(i) - 4 hat(j) + 6hat(k)` `-hat(i) - 2hat(j) + 6hat(k)` NONE of these. Solution :`vec(B) + (2hati +4hatj-6hatj)=hati` `vec(B)=-hati-4hatj+6hatk`

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Given vec(A) = 2hat(i) + 4hat(j) -6hat(k). When a vector vec(B) is added to vec(A) , we get a unit vector along x-axis. Then vec(B) is :

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