Saved Bookmarks
| 1. |
Given : vec(a) + vec(b) + vec(c) = 0 . Out of the three vectors vec(a), vec(b) and vec(c) , two are equal in magnitude. The magnitude of the third vector is sqrt(2) times that of either of the two having equal magnitude. The angles between the vectors are : |
|
Answer» 90°, 135°, 135° Given `veca + VECB + vecc=0` or `veca +vecb=-vecc` or `(veca+vecb).(veca+vecb)=(-vecc).(-vecc)` or `a^(2)+a^(2)+2a^(2)costheta=2a^(2)` or `vec(b)+vecc=-veca` or same as above or `a^(2)+2a^(2)+2(a)(sqrt(2)a)costheta=a^(2)` or `costheta=-(2a^(2))/(2sqrt(2)a^(2))=-1/sqrt(2)` `theta=135^@` SIMILARLY, we can work out the third angle. |
|