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Given y=x2. As x→2,y→4 what is the value of δ be for which from |x−2|<δ it follows that |y−4|< ∈ =0.001? |
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Answer» Given y=x2. As x→2,y→4 what is the value of δ be for which from |x−2|<δ it follows that |y−4|< ∈ =0.001? |
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