1.

Givenfor Sn^(4+)//Sn^(2+) standard reduction potential is 0.15 V and for Au^(3+) //Au standard reductionpotentialis 1.5 V for the reaction 3 Sn^(2)+2 Au^(3+) rarr 3Sn^(4+)+2ASu The value of E_(cell)^(@) is

Answer»

`+1.35`
`+2.55`
`-1.35`
`-2.55`

Solution :`E_(CELL)^(2)=E_(cathode)^(2) -E_(ANODE)^(@) =1.5 -0.15 =1.35 V`


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