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Glucose or sucrose are soluble in water but cyclohexane or benzene (simple six membered ring compounds) are insoluble in water.Explain. |
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Answer» Solution :Glucose contains five and sucrose contains eight `-OH` groups. These `-OH` groups form H-bonds with water. Due to this extensive intermolecular H-bonding, glucose and sucrose are soluble in water irrespective of the fact that their molecular masses are `180 "G MOL"^(-1)` and `342 "g mol"^(-1)` respectively. In contrast , benzene (molecular mass `= 78 "g mol"^(-1)`) and cyclohexane (molecular mass `=84 "g mol"^(-)`) are simple molecules having low molecular masses. Even than they are insoluble in water. The reason being that these COMPOUNDS do not contain`-OH` groups and hence do not form H-bonds with water. ALTERNATIVELY,like DISSOLVES like is the general rule of solubility. THerefore, benzene and cylohexane which are non - polar molecules do not dissolve in polar water molecules while glucose and sucroe being polar molecules dissolve in polar water molecules. |
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