1.

Glucose when treated with CH_(3)OH in presence of dry HCl gas gives alpha and beta methylglucosides because it contains

Answer»

an aldehydic group
a `-CH_(2) OH` group
a RING structure
five-OH groups

Solution :Because of the ring structure, `C_(1)` in glucose becomes chiral and hence glucose exists in two stereoisomeric forms i.e., `alpha` -and `beta`-CORRESPONDING to each stereoisomeric form, glucose forms two methyl glucosides, i.e., `alpha`-and `beta`-methylglucosides.


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