1.

Glutamic acid, H_(2)N-CH(CH_(2)COOH)-COOH has pK _(a_(1))(alpha-COOH)=2.2, pK_(a_(2))(alpha-NH_(3))=9.8 and pK_(a_(3))=("R group"COOH)=4.3. The isoelectric point of glutamic acid is

Answer»

`5.9`
`7.0`
`10.2`
`3.2`

Solution :`{:(H_(3)overset(+)-CH-COOH),(""|),(""CH_(2)CH_(2)COOH),("""Cationic form"):} overset("On NEUTRALIZATION")underset("1st ionization")to`
`{:(H_(3)overset(+)N-CH-COO^(-)),(""|),(""CH_(2)CH_(2)COOH):}`
`underset("2 ND ionization")to {:(H_(3)overset(+)-CH-COO^(-)),(""|),(""CH_(2)CH_(2)COO^(-)):}`
Isoelectric point `(pI)=(pK_(a_(1))+pK_(a_(2)))/(2)=(2.2+4.3)/(2)=3.25`


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