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Gold has a specific heat of 130Jkg*""^(@)C and wood has a specific heat of 1,800Jkg*""^(@)C. If a piece of gold and a piece of wood, each of mass 0.1 kg, both absorbs 2.340 J of heat, by how much will their temperatures rise? |
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Answer» SOLUTION :We're given c,m, and Q, and we know that `DeltaT=Q//(MC)`. `DeltaT_("gold")=(Q)/(mc_("gold"))=(2.340J)/((0,1kg)(130J//kg*""^(@)C))=180^(@)` `DeltaT_("wood")=(Q)/(mc_("wood"))=(2,340J)/((0,1kg)(1,800J//kg*""^(@)C))=13^(@)C` NOTICE that the temperature of gold increased by `180^(@)C`, but the temperature of the wood increased by only `13^(@)C`. |
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