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Gold nucleus (""_(79)^(198)Au) can decay into mercuyr nucleus (""_(80)^(198)Hg^(8)) by two decay schemes shown in figure below (i) it can emit a beta -particle (beta_(1)) and come to ground state by either emiting one gamma- ray ( gamma_(1)) or emitting two gamma- rays (gamma_(3) and gamma_(4)) (ii) It can emit one beta- particle (beta_(2)) and come to ground state by emitting gamma_(2) ray. Atomic masses: ""^(198)Au=197.9652 amu and ""^(198)Hg=197.9662 amu. Given that 1 amu= 930MeV//c^(2). The energy levels of the nucleus are shown in figure below Whatis the maximum kinetic energy of emitted beta_(2) particle? |
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Answer» 1.44 MeV |
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