1.

Gold nucleus (""_(79)^(198)Au) can decay into mercuyr nucleus (""_(80)^(198)Hg^(8)) by two decay schemes shown in figure below (i) it can emit a beta -particle (beta_(1)) and come to ground state by either emiting one gamma- ray ( gamma_(1)) or emitting two gamma- rays (gamma_(3) and gamma_(4)) (ii) It can emit one beta- particle (beta_(2)) and come to ground state by emitting gamma_(2) ray. Atomic masses: ""^(198)Au=197.9652 amu and ""^(198)Hg=197.9662 amu. Given that 1 amu= 930MeV//c^(2). The energy levels of the nucleus are shown in figure below The wavelength of emitted gamma - rays is the order

Answer»

`lamda_(2)gtlamda_(3)GT lamda_(1)`
`lamda_(3)gtlamda_(2)gtlamda_(1)`
`lamda_(1)gtlamda_(2)gtlamda_(3)`
`lamda_(3)=lamda_(2)=lamda_(1)`

Answer :A


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