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Goldis 19 times a heavy as water andcopper is 9 times as heavy is water. In what ratio should these be mixed toget an alloy 15 times as heavy is waster?`1:1`b. `1:2`c. `2:3`d. `3:2`

Answer» Let the weight of water be Wtherefore, weight of gold `=19W`
and weight of copper `=9W`
therefore weight of alloy `=15W`
Ratio of G:C = 1:y
Therefore total = 1+y
`19W+y(9W)= (1+y)15W`
`19W+9yW = 15W+15Wy`
`4W = 6Wy`
`y = (6W)/(4W)`
`y = 3:2`
which is the required ratio.


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