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Good evening ❤❤Today's Question ✌Q.Calculate the compound interest for the second year on ₹8000 invested for 3 yrs at 10%p.a.Also find the sum due at the end of third year.no spamming otherwise______​

Answer»

cosA=5/13

sinA=-√(1-cos^2A) (since theta is in 4TH quadrant)

i.e. sinA=-√144/169

=-12/13

tanB=-15/8

sinB=+(15)/√{(-15)^2+(8)^2} (B is in Q2)

i.e. sinB=15/17

cosB=tanB/sinB

i.e. cosB=-15/8 * 17/15

cosB=17/8

now

sin(A+B)=sinAcosB+cosAsinB

sin(A+B)=(-12/13)(17/8)+(5/13)(15/17)

={1/13}(-51/2 + 75/17)

=(1/13)(-710/34)

=-710/442


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