InterviewSolution
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InterviewSolution
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Graviational acceleration on the surface of plane fo `(sqrt6)/(11)g.` where g is the gracitational acceleration on the surface of the earth. The average mass density of the planet is `(2)/(3)` times that of the earth. If the escape speed on the surface of the earht is taken to be `11 kms^(-1)` the escape speed on teh surface of the planet in `kms^(-1)` will beA. `3`B. `6`C. `9`D. `12` |
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Answer» Correct Answer - A `g=(GM)/(R^(2))=(G(4/3piR^(3))rho)/(R^(2))` `gproprhoR, Rpropg/rho` Now escape velocity, `v_(e)=sqrt(2gR)` `v_(e)propsqrt(gR), v_(e)propsqrt(gxxg/rho)propsqrt((g^(2))/rho)` `(v_(e))_("planet")=(11kms^(-1))sqrt(6/121xx3/2)=3 km s^(-1)` |
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