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InterviewSolution
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Gravitational field at the surface of a solid sphere is `1.5 xx 10^(-4) "N kg"^(-1)`. Find the gravitational field at a point situated inside the sphere at a distance equal to half of rhe radius of the solid sphere. |
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Answer» Let mass of the solid sphere is M and radius is R Its is given that `E_("surface")=(GM)/(R^(2))=1.5xx10^(-4)` `:. E(r=R//2)=(GM)/(R^(3))(R//2)` `=(GM)/(2R^(2))=(1.5 xx 10^(-4))/(2)` `=7.5xx10^(-4)"N kg"^(-1)`. |
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