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Guys pls answer me as soon as possible plss |
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Answer» B is diameter, angle ACB = 90°Also, we have AC = BCtherefore, angle CAB = angle CBA = p (ASSUME)Now, in ∆ ACBangle ACB = 90°angle CAB = pangle CBA = pso, by angle sum propertyangle ACB + angle CAB + angle CBA = 180°90° + p + p = 180°2p = 90°p = 45°Hence, angle CAB = 45° |
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