[H=1, C=12,O=16, Na=23, P=31,S=32] {:("Column-I","Column-II"),((A)4.1 g H_2SO_3,(p)"200 ml of 0.5 N NaOH is used forcomplete neutralization"),((B)4.9 g H_3PO_4,(q)"200 millimoles of oxygen atoms"),((C )4.5 g "oxalic acid"(H_2C_2O_4),(r)"Central atom has its highest oxidation number"),((D)4.3 g Na_2CO_3,(s)"May react with an oxidising agent"),(,(t)"Shape around central atom is regular"):}

[H=1, C=12,O=16, Na=23, P=31,S=32] {:("Column-I","Column-II"),((A)4.1

1.	[H=1, C=12,O=16, Na=23, P=31,S=32] {:("Column-I","Column-II"),((A)4.1 g H_2SO_3,(p)"200 ml of 0.5 N NaOH is used forcomplete neutralization"),((B)4.9 g H_3PO_4,(q)"200 millimoles of oxygen atoms"),((C )4.5 g "oxalic acid"(H_2C_2O_4),(r)"Central atom has its highest oxidation number"),((D)4.3 g Na_2CO_3,(s)"May react with an oxidising agent"),(,(t)"Shape around central atom is regular"):}
Answer» <P> SOLUTION :(A)4.1 gm =`4.1/82` mole `H_2SO_3`=50 m mole 2NaOH+`H_2SO_3toNa_2SO_3+2H_2O` m moles of NaOH requries =2 x m mole of `H_2SO_3` =100 =m mole of NaOH present (200 ml x 0.5 N) HIGHEST O.N. of S= +6 (B)`4.9 gm =4.9/98` mole =50 m mole of `H_3PO_4` =200 m mole 'O' atom Highest O.N. of P = +5 (C )4.5 gm =`4.5/90` =50 m mole `H_2C_2O_4` (di basic acid) m mole of NaOH requires =2 x 50 =100 Highest O.N. of C = +4 (D)5.3 gm =`1/20` mole `Na_2CO_3` It do not reacts with NaOH and m mole of O atom =`1/20xx1000xx3=150`