InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
h 10 ml of H to form water. When 200 ml of H2 at STP is passedthe Cuo loses 0.144 g of its weight. Does the above data correspondd p.n hond order on Po ion.to the law of constant composition?3- |
|
Answer» In the second experiment 0.144 g weight is lost from CuO. This is due to the reduction of CuO into Cu. In other words, 0.144 g oxygen combined with 200 mL H 2.32 g oxygen occupies 22400 mL volume at STP.0.144 g oxygen will occupy = 22400 x 0.144/ 32= 100.8 mL-O23It means the ratio of H2 and O2 in water is 200 : 100.8 =2: 1. The same ratio is in first case (10:5 or 2:1). Thus, the law of constant composition is proved. thanks |
|