1.

H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta = -68.39 kcal K + H_(2)O rarr KOH + (1)/(2) H_(2), Delta H = -48 kcal KOH + Water rarr KOH (aq), Delta H = -14 kcal The heat of formation of KOH in kcal is :

Answer»

`-34.39 KCAL`
102.39 kcal
34.39 kcal
130.39 kcal

Answer :B


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