H_2+1/2O_2rarrH2O, triangle H=-68.39 kcal (i) K+aqrarrKOH(aq)+1/2H_2, – InterviewSolution

1.	H_2+1/2O_2rarrH2O, triangle H=-68.39 kcal (i) K+aqrarrKOH(aq)+1/2H_2, triangleH=-48 kcal (ii) KOH+aqrarrKOH(aq): triangleH=-14 kcal (iii)T he heat of formation(in kcal) of KOH is:
Answer» `-68.39+48-14` `-68.39-48-14` `68.39-48+14` 68.39+48+14 Answer :B

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