`H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l)` `BE (H-H) = x_(1), BE (O=O)=x_(2)` `BE(O=H)=x_(3)` Latent heat of vaporisation of water liquid into water vapour `=x_(4)`, then `Delta_(f)H` (heat of formation of liquid water) isA. `x_(1) +(x_(2))/(2) -x_(3) +x_(4)`B. `2x_(3)-x_(1) -(x_(2))/(2)-x_(4)`C. `x_(1)+(x_(2))/(2)-2x_(3)-x_(4)`D. `x_(1)+(x_(2))/(2)-2x_(3)+x_(4)`

`H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l)` `BE (H-H) = x_(1), BE (O=O)

1.	`H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l)` `BE (H-H) = x_(1), BE (O=O)=x_(2)` `BE(O=H)=x_(3)` Latent heat of vaporisation of water liquid into water vapour `=x_(4)`, then `Delta_(f)H` (heat of formation of liquid water) isA. `x_(1) +(x_(2))/(2) -x_(3) +x_(4)`B. `2x_(3)-x_(1) -(x_(2))/(2)-x_(4)`C. `x_(1)+(x_(2))/(2)-2x_(3)-x_(4)`D. `x_(1)+(x_(2))/(2)-2x_(3)+x_(4)`
Answer» `DeltaH = (BE)_("reactant") -(BE)_("products")` [But all the species must be in gaseous state. In product, `[H_(2)O(l) rarr H_(2)O(g)] DeltaH` must be added. Hence, `H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l)` `DeltaH = [(BE)_(H-H)+(1)/(2)(BE)_(O=O)]` `= [(DeltaH)_(vap) +2(BE)_(O-H)]` `= x_(1) +(x_(2))/(2) -[x_(4)+2x_(3)]` `= x_(1) +(x_(2))/(2) -x_(4) - 2x_(3)`

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