H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l) , Delta H at 298 K = - 285.8 kJ – InterviewSolution

1.	H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l) , Delta H at 298 K = - 285.8 kJ The molar enthalpy of vapourization of water at 1 atm and 25^(@)C is 44 kJ. The standard enthalpy of formation of 1 mole of water vapour at is
Answer» `-241.8 KJ` 241.8 kJ 329.8 kJ `-329.8 kJ` ANSWER :A

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