H_2(g)+1/2O_2(g)=H_2O(l), triangleH_298k=-68.32 kcal. Heat of vaporis – InterviewSolution

1.	H_2(g)+1/2O_2(g)=H_2O(l), triangleH_298k=-68.32 kcal. Heat of vaporisation of water at 1 atm and 25^@C is 10.52 kcal. The standard heat of formation(in kcal) of 1 mole of water vapour at 25^@C is:
Answer» `-78.84` 78.84 `+57.80` `-57.80` ANSWER :D

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