1.

H_(2)(g)+Cl_(2)(g)rarr2HCl(g).DeltaH=-44 kcal2Na(s)+2HCl(g)rarr2NaCl(s)+H_(2)(g), DeltaH=-152 kcalFor the reaction Na(s)+(1)/(2)Cl_(2)(g)rarrNaCl(s),DeltaH=

Answer»

`-108 kcal`
`-196 kcal`
`-98 kcal`
54 kcal

Solution :By (i) + (ii) ,
`Na+(1)/(2)Cl_(2)RARRNACL, DELTAH=-(196)/(2)kcal=-98kcal`.


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