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`H_(2)(g) + Cl_(2) rarr 2HCl (g), Delta H = -44K.cals 2 Na(s)+2HCl (g)rarr 2NaCl(s)+H_(2)(g), Delta H = -152K.cal` `Na(s)+(1)/(2)Cl_(2)(g) rarr NaCl(s), Delta H = ?`A. `+108K.cal`B. `-196 K.cal`C. `-98 K.cal`D. `50 K.cal` |
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Answer» Correct Answer - C `Delta H = H_(P-H_(R))` |
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