H_(2)(g) + I_(2) hArr 2HI(g): Delta H = 12.40 kcal. According to this – InterviewSolution

1.	H_(2)(g) + I_(2) hArr 2HI(g): Delta H = 12.40 kcal. According to this reaction, heat of formation of HI will be
Answer» 12.4 KCAL `-12.4 kcal` `-6.20 kcal` 6.20 kcal Answer :D

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