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`H_(2)O(l)toH_(2)O(g)` , `DeltaH=+43.7 kJ` `H_(2)O(s)toH_(2)O(l)` , `DeltaH=+6.05kJ` The value of `DeltaH_((sublimation))` of ice isA. `49.75 kJ mol^(-1)`B. `37.65 kJ mol^(-1)`C. `43.7 kJ mol^(-1)`D. none of these

Answer» Correct Answer - A
Add the two equations to get
`H_(2)O(s) to H_(2)O(g)`


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