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`H_(2)S` acts only as reducing agent while `SO_(2)` can act both as a reducing agent and as an oxidising agent. How will you account for it ?

Answer» In `H_(2)S`, the oxidation state of sulphur is - 2. It can only increase its oxidation state but cannot decrease it. Therefore, it can act only as a reducing agent. In `SO_(2)`, the oxidation state of sulphur is + 4. It is in a position to undergo a decrease as well as an increase in the oxidation state. Thus, `SO_(2)` can act both as an oxidising agent and a reducing agent.


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