H_2 S in the presence of HCl precipitate group II but not group IV because
Answer»
HCl ACTIVATES `H_(2)S` HCl incraeses the concentration of `Cl^(-)` HCl decreases the concentration of `S^(2-)` ions HCl LOWERS the solubility of `H_(2)S` in the solution
Solution :Due to common ion effect, HCl suppresses the IONISATION of `H_(2)S` thus decreasing the concentration of `S^(2-)` ions. Only GROUP II radicals are precipitated.