1.

H_2 S react with O_2 in restricted supply of O_2 to form

Answer»

`H_(2)O + S`
`H_(2)O + SO_(2)`
`H_(2)O + SO_(3)`
`H_(2)SO_(4) + S`

Solution :`2H_(2)S +O_(2) to 2H_(2)O +2S`
If the `O_(2)` supply is not RESTRICTED
`2H_(2)S +3O_(2) to 2H_(2)O +2SO_(2)`


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