1.

H_(2)SO_(4) cannot be used to prepare HBr from NaBr as it

Answer»

Reacts slowly with NaBr
Oxidises HBR
Reduces HBr
DISPROPORTIONATE HBr

Solution :HBr is not preparedby HEATING NaBr with conc. `H_(2)SO_(4)` because HBr is a strong REDUCING agent and reduce `H_(2)SO_(4)` to `SO_(2)` and get itself oxidised to bromine.
`NaBr + H_(2)SO_(4) to NaHSO_(4) +HBr`
`H_(2)SO_(4) +2HBr to SO_(2) +Br_(2) +2H_(2)O`


Discussion

No Comment Found

Related InterviewSolutions