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| 1. |
H-2ユcalculate the percentage degree of dissociation of an electrolyte XY2 (Normal molar mass164) inwater if the observed molar mass by measuring elevation in boiling point is 65.6 |
| Answer» <p>The compound XY2 will dissociate as</p><p>XY2>>>>>X+2Y</p><p>Thus, the Van't Hoff factor will be given by 1+2d where d is the degree of dissociation.</p><p>But by definition, Van't Hoff factor is given by Normal mass/Observed mass. In this case, 164/65.6=2.5</p><p>Thus, by equating above two equations:</p><p>1+2d=2.5 which implies that d=0.75</p><p>Thus, percentage dissociation is 0.75×100=75%</p><p>The answer is 75%</p> | |