1.

H_(3)C-underset(CH_(3))underset(|)(C)H-CH=CH_(2)+HBr to A A (predominantly) is

Answer»

`CH_(3)-UNDERSET(Br)underset(|)(C)H-underset(CH_(3))underset(|)(C)H-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(C)H-underset(Br)underset(|)(C)H-CH_(3)`
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)-CH_(2)Br`
`CH_(3)-underset(CH_(3))underset(|)overset(Br)overset(|)(C)-CH_(2)CH_(3)`

Solution :
THUS, option (d) is correct.


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