1.

H_3C-undersetunderset(CH_3)|CH-overset+CH=CH_2+HBr to A A (Predominantly ) is

Answer»

`CH_3-undersetunderset(BR)|CH-undersetunderset(CH_3)|CH-CH_3`
`CH_3-undersetunderset(CH_3)|CH-undersetunderset(Br)|CH-CH_3`
`CH_3-undersetunderset(CH_3)(|)CH-CH_2-CH_2Br`
`CH_3-undersetunderset(CH_3)(|)oversetoverset(Br)(|)C-CH_2CH_3`

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