1.

H_3PO_3+HNO_3+(NH_4)_2MoO_4to Oxidation number of Mo in product is x. Cr_2O_7^(2-)+H^(+)+NaCl to Oxidation state of Cr in product is y. SCN^(-)+MnO_2toNumber of pi bonds in sulphur containing product is z. Find x+y+z

Answer»


SOLUTION :x=+6`(NH_4)_3 PMo_12O_40`
y=+6 `CrO_2Cl_2`
z=4
`ZtoN^(@)C-S-S-C^(@)N`


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