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Ha right angle triangle ABC, right angle is at B. If tanA =√3 then find the value of i)sinA cosC+cosA sinC |
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Answer» AnswerGiven thattanA= 13 AC= ( 3 ) 2 +1 2 = 3+1 = 4 =2 now(i)sinAcosC+cosAsinC= 23 × 23 + 21 × 21 = 43 + 41 = 44 =1 and (II)cosAcosC−sinAsinC= 21 × 23 − 21 × 23 = 43 − 43 =0 |
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