Half a mole of helium is contained in a container at S.T.P. How much heat energy is needed to double the pressure of the gas, keeping the volume constant ? Heat capacity of the gas is 3J/g/K:

Half a mole of helium is contained in a container at S.T.P. How much h

1.	Half a mole of helium is contained in a container at S.T.P. How much heat energy is needed to double the pressure of the gas, keeping the volume constant ? Heat capacity of the gas is 3J/g/K:
Answer» 1.638 J 16.38 J 163.8 J 1638 J. Solution :Here `C_(v)=M XX C_(v) =4xx3=1` J/mole/K at constant volume `(P_(2))/(P_(1))=(T_(2))/(T_(1))=2" or "T_(2)=2 T_(1)` HEAT required, `Delta Q =(1)/(2) xx12xx(2T_(1)-T_(1))` `=(1)/(2)xx12xx273=1638 J`. `therefore` CORRECT choice is (d).

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Half a mole of helium is contained in a container at S.T.P. How much heat energy is needed to double the pressure of the gas, keeping the volume constant ? Heat capacity of the gas is 3J/g/K:

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