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Half life of ""^(226)Ra is 1600 years.How many distintegrations per second occur in 1 gram of ""^(226)Ra ? |
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Answer» Solution :Data SUPPLIED, `T_(1//2) = 1600 yrs, LAMBDA = 0.6931//T_(1//2)` No. of atoms in one gram of `Ra^(226), N = (1 xx 10^(-3))/(226) xx 6.023 xx 10^(23)` `(DN)/(DT) = lambda N = (0.6931)/(1600) xx (6.023 xx 10^(20))/(226) = 1.1545 xx 10^(15)` PER year `i.e, (dN)/(dt) = 3.661 xx 10^7 "per sec" = (3.661 xx 10^7)/(3.7 xx 10^(10)) = 0.99 xx 10^(-3) Ci` |
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