1.

Half-life of a reaction is found to be inversely proportional to the cube of initial concentration. The order of reaction is

Answer»

5
2
4
3

Solution :The half-life period of `N^(TH)` ORDER reaction is
`t_(1//2)=(K)/(a^(n-1))`
a is the initial concentration of reactant.
`t_(1//2)prop(1)/(a^(3))""thereforet_(1//2)=(K)/(a^(3))`
`(K)/(a^(n-1))=(K)/(a^(3))impliesa^(3)=a^(n-1)`
`impliesn-1=3impliesn=4`.
`therefore`The order of the reaction is 4.


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