1.

Half life period of a first-order reaction is 1386 seconds . The specific rate constant of the reaction is

Answer»

`5. 0 xx 10^(-3) s^(-1)`
`0.5 xx 10^(-2) s^(-1)`
`0.5 xx 10^(-3) s^(-1)`
`5.0 xx 10^(-2) s^(-1)`

SOLUTION :`t_(1//2) = (0.693)/(k) , k = (0.693)/(1386) = 0.5 xx 10^(-3) s^(-1)`.


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