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Half life period of a radio active element is 1500 years. Find the value of disintegration constant interms of second. |
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Answer» SOLUTION :`LAMBDA=(0.693)/(t^(1//2)) =(0.693)/(1500 yrs)` `=(0.693)/(1500xx365xx24xx60xx60 sec)` `=0.1465 xx10^(-10) sec^(-1)` |
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