1.

Half lives of first order anda zero order reaction are same . Then the ratio of the initial rates of the first order reaction to that of the zero order reaction is

Answer»

`(1)/(0.693)`
` 2xx0 .693 `
`0.693`
`(2)/(0.693)`

Solution :`t_(1//2)` for zero order = `([A]_(0))/(2K)`
`t_(1//2)` for first order = `(0.693)/(K')`
Rate = Initial rate , when `[A_(0)] = 1`
So , `(1)/(2k) = (0.693)/(k')` or `(k')/(k) = 2 xx 0.693`.


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