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Half-lives of two radioactive substances `A` and `B` are respectively `20` minutes and `40` minutes. Initially, he sample of `A` and `B` have equal number of nuclei. After `80` minutes the ratio of the remaining number of `A` and `B` nuclei is :A. `5 : 4`B. `1 : 16`C. `4 : 1`D. `1 : 4` |
Answer» Correct Answer - A `t=80 min=4 T_(A)=2T_(B)` `:.` no. of nuclei of A decayed `=N_(0)-N_(0)/2^(4)=(15 N_(0))/16` `:.` no. of nuclei of B decayed `=N_(0)- N_(0)/2^(2)=(3N_(0))/4` required ratio `=5/4` |
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