1.

Half the period of a first order reaction is 1386 seconds . The specific rate constant of the reaction is :

Answer»

`0.5xx10^(-2) s^(-1)`
`0.5xx10^(-3)s^(-1)`
`5.0xx10^(-2) s^(-1)`
`5.0xx10^(-3) s^(-1)`

SOLUTION :(B)`t_(1//2)=(0.693)/(K) `
or `k = (0.693)/(t_(1//2))`
`= (0.693)/(1386) = 0.5 xx10^(-3) s^(-1)`


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