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Halp me answer this question 1-z to z - 1 |
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Answer» Step-by-step explanation:|z| = 1 Solution : LET z = X + IY. Then, z−1z+1=(x−1)+iy(x+1)+iy×(x+1)−iy(x+1)−iy=(x2+y2−1)+(x+y)i(x+1)2+y2 Now, z−1z+1 is PURELY imaginary ⇔x2+y2−1=0⇔x2+y2=1⇔|z|=1 |
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