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Hardness of water is 200 ppm. The normality and molarity of `CaCO_3` in the water is (a). `2xx10^(-6)(N,2xx10^(-6)M` (b). `4xx10^(-2)N,2xx10^(-2)M` (c). `4xx10^(-3)N,2xx10^(-3)M` (d). `4xx10^(-1)N,2xx10^(-1)M` |
Answer» Hardness is weight in grams of `CaCO_3` in `10^(6) mL` of `H_2O` `or=10^(6)` of `H_2O` `(becausedH_2O=1)` `Mw(CaCO_3)=100gmol^(-1)` `M=(W_2xx1000)/(Mwxx"Volume of solutio in mL")` `=(200xx1000)/(100xx10^(6))=2xx10^(-3)M` `N=nxxM=2xx2xx10^(-3)=4xx10^(-3)N` |
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